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Question 1. The reading tA and tB of two centigrade scale thermometers A and B graded at ice point 0°C and steam point 100°C are related by the equation tA=l +mtB+n(tB)², where l, m,n are constants. When both are immersed in oil then thermometer A reads 51°C and thermometer B reads 50 °C. determine the reading on thermometer A when thermometer B reads 25°C? Comment on the question "which thermometer is correct".
Thermodynamics Question solution, Chapter1 Zeroth law of thermodynamics. Question 1. The reading tA and tB of two centigrade scale thermometers A and B graded at ice point 0°C and steam point 100°C are related by the equation tA=l +mtB+n(tB)², where l, m,n are constants. When both are immersed in oil then thermometer A reads 51°C and thermometer B reads 50 °C. determine the reading on thermometer A when thermometer B reads 25°C? Comment on the question "which thermometer is correct". Ans- tA=l+mtB+n(tB)² According to question tA=tB=0°C tA=l+mtB+n(tB)² 0=l+0+0 l=0 Second step tA=tB=100°C tA=l+mtB+n(tB)² 100=0+m×100+n(100)² m+100n=1 ----------------------------(1) For tA=51°C tB=50°C tA=l+mtB+n(tB)² 51=0+M50+n(50)² -----------------------------(2) Now using equation (1) and (2) find m&n 50m+2500n=51 50m+5000n=50 - - - ________________ 0 -2500n=1 n=-1/2500 Put value of 'n' in equati
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