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Question2. A new temperature scale N is to be defined. The boiling and freezing points of water on this scale are 100°N amd 400°N respectively. Then (a) what will be the reading on the new scale corresponding to 60°C? (b) At what temperature both the Celsius and new temperature scale reading would be same?

 THERMODYNAMICS 

Chapter 1. ZEROTH LAW OF THERMODYNAMICS

Question2. A new temperature scale N is to be defined. The boiling and freezing points of water on this scale are 100°N amd 400°N respectively. Then (a) what will be the reading on the new scale corresponding to 60°C? (b) At what temperature both the Celsius and new temperature scale reading would be same?

Sol:

ts= boiling temperature 

ti= ice temperature 

tc=corresponding temperature 

 scale reading:         boiling temperature    corresponding          freezing temperature

 new scale                             100°N                       x°N                            400°N

Celsius scale                         100°C                       60°C                           0°C


Celsius scale = new scale


ts - ti/ts - tc     =  ts - ti/ts - tc  

100 - 0/100 - 60 = 100°N - 400°N/100°N - X°C

100/40 = -300°N/100°N - X°N

100°N - X°N = -120°N

   X = 220°N


(b)  both Celsius and new temperature scale value same at 100°


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